Physics, 27.06.2019 09:30 lilyella1004

A12kw motor moves a 1000kg car at what constant velocity, if the motor applies a force that equals 2000n? also, of the motor for 2.75s, what amount of work has the motor done on the car. (show working out)

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Answer from: isabelperez063

Given data

Power = 12 KW ,

mass (m) = 1000 kg ,

Force (F) = 2000 N ,

time (t) = 2.75 s

Determine

1. Velocity (v) = ?

2. Work (W) = ?

We know that Power (P) = Rate of doing work

= ( Work ÷time) KW

Also we know that Work = F × displacement

Force = m.a N

=> 2000 = 1000 × a

=> a = 2 m/s²

And we know that acceleration (a) = rate of change of velocity

= v ÷ t

=> v = a × t

= 2 × 2.75

= 5.5 m/s

Now determine the Power P = Work done ÷ time

12 = W ÷ 2.75

W= 12 ×2.75

= 33 KJ

= 33000 J

Answer from: Quest

answer: the correct answer id option(d).

explanation:

snell's law refraction:

$\frac{n_2}{n_1}=\frac{sin \theta_1}{sin\theta_2}$

the angle of refraction = $\theta_2=38 ^o$

the angle of incidence = $\theta_1=?$

refractive index of air = $n_1$ = 1

refractive index of glycerol $n_2$ = 1.47

$\frac{1.47}{1}=\frac{sin\theta_1}{sin 38^o}, (sin38^o=0.61)$

$sin\theta_2=0.8967$

$\theta_2=24.2^o, (sin^{-1}0.8967=63.72^o)$

from the given options, the most closest answer to 63.72° is 65° of option (d).

Answer from: Quest

where is the circuit diagram ?

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