Asatellite of mass m is moving in a circular orbit around the earth at a constant speed v and at an altitude h above the earth's surface. a. find the speed of a satellite orbiting the earth 1000 km above its surface. the radius of the earth rearth = 6371 km is and its mass is mearth = 5.98x1024 kg .

The satellite executes a rotation motion around the earth, because Earth's force of attraction plays the role of centripetal force:

Fa=Fcp=>k*Mp*m/(Rp+r)²=mv²/(Rp+r)=>v=√(k*Mp/(Rp+r))=√(6.67*10⁻¹¹*5.98*10²⁴/(6371*10³+1000*10³))=√(39.88*10¹³/(7371*10³))=√(5.41*10⁷)=7355.53 m/s

Check the calculations again !

i believe the answer is a hope it and is correct

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2