If you have a 1.5 l container of tea and the label state that the container contains 1.2 g of sugar grams of sugar what's the concentrated of sugar in the tea

Given data

mass of solute (m) = 1.2 g ,

Volume of solution  = 1.5 L ,

                                 = 1.5 × 1000 mL

                                 = 1500 mL ,

What is the concentration of solution = ?

                                 concentration = (mass of solute) ÷ (100 mL of solution)

                                                         = (1.2) ÷ (1500 mL of solution)

Note: remember to divide both numerator and denominator by 15 to get concentration per 100 ml

                    Therefore concentration  = 0.1 /100 mL ;

The concentration of sugar in a tea is  0.1/100 mL

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts