What's the surface temperature of a woodstove with surface area 1.4 m2 that radiates energy at the rate of 18 kw? treat the stove as a blackbody?

Assuming the emissivity is 1.0, the temperature of the wood stove will be about 417 C

Explanation:

You can use the Stefan-Boltzmann formula tying energy with temperature of a blackbody:

P - rate of radiation

is the blackbody's emissivity

is the Stefan-Boltzmann constant

A - area

T - temperature

So,

Assuming the emissivity ( a number between 0 and 1) is 1.0, the temperature of the wood stove will be about 417 C. The emissivity number was not given in your question. If you determine what it is, you can divide this result by the fourth power of that value to get an updated result.

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )