Aset of data is collected for objects in an inelastic collision, as recorded in the table. to identify the momentum of object 1, you must multiply (a. elapsed time b. mass c. acceleration and (a. elapsed time b. applied force c. velocity) to find momentum. object 1 had a momentum of (a. 2.0 b. 4.0 c. 8.0) kg ∙ m/s before the collision. object 2 had a momentum of (a. 0.0 b. 6.0 c. 8.0) kg ∙ m/s before the collision. the combined mass after the collision had a total momentum of . (a. 14.0 b. 10.0 c. 8.0) m(kg) v(m/s) p (kg . m/s) object 1 2.0 4.0 object 2 6.0 0 object 3 8.0 1.0

A body in motion has momentum. It is the product of mass and velocity.

To identify the momentum of object 1, we mus multiply B. mass and C. velocity.

Mass of object 1 is: 2.0 kg and velocity is 4.0 m/s

So, the momentum of the object 1 is:

P = m v

⇒ P = 2.0 kg × 4.0 m/s = 8.0 kg m/s

Thus, Object 1 had a momentum of C. 8.0 kg ∙ m/s before the collision.

Mass of Object 2: 6.0 kg

Velocity of object 2 = 0

Thus, Object 2 had a momentum of A. 0.0 kg.m/s before the collision.

Mass of object 3: 8.0 kg

velocity of object 3: 1.0 m/s

Momentum of object 3 before collision=  8.0 kg × 1.0 m/s = 8.0 kg.m/s

From law of conservation of momentum, initial momentum is equal to final momentum.

Initial momentum = (8 + 0 + 8) kg.m/s = 16.0 kg.m/s

Thus, the combined mass would have a total momentum =  16.0 kg.m/s after collision.

The combined mass ( 2+6+8 = 16 kg) would move with the velocity of:

v = P/m = (16.0 kg.m/s )/16 kg = 1 m/s after collision.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

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