Suppose a piece of dust finds itself on a cd. if the spin rate of the cd is 355 rpm, and the piece of dust is 4.5 cm from the center, what is the total distance (in m) traveled by the dust in 8 minutes? (ignore accelerations due to getting the cd rotating.) m

we know that 1 rpm =

w = angular speed of cd  = 355 rpm =   = 37.2

r = distance from the center for piece of dust = 4.5 cm = 0.045 m

v = speed of motion for piece of dust = ?

Speed is given as

v = r w

inserting the values

v = (0.045) (37.2)

v = 1.67

t = time of travel for piece of dust = 8 min = 8 x 60 sec = 480 sec        (Since 1 min = 60 s)

d = distance traveled by piece of dust = ?

Distance traveled by piece of dust  is given as

d = v t

inserting the values

d = (1.67) (480)

d = 801.6 m

15.3 cos 65 degrees trig