5m/swhenhereaches and even steeper slope. if he accelerates at 2 m/s2 for the 5 m slope, how fast is he traveling when he reaches the bottom of the 5 m slope?

Answer :   v = 6.7 m/s

Explanation :

It is given that :

Initial velocity, u = 5 m/s

Acceleration,

Distance, s = 5 m

Using equation of motion:

So, when he reaches the bottom of 5 m slope he is travelling with travelling with 6.7 m/s.

this could be newton#'s law of cooling. the cooling curve is exponential