Forces used for the normal fault in british columbia canada

i would think form in reponse to tensional forces

it breaks and dirupture other materials and other sencews from the bottom

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.