An 800 kg car is moving at 32 m/s. what magnitude force is needed to bring that car to a stop in 30 seconds?

Kinematic relationship to get acceleration:

vf2 - vi2 = 2ax

vf = final speed = 0 m/s (comes to a full stop)

vi = initial speed = 32.0 m/s

x = distance over which the accelerating force acts to bring about a full stop = 30.0 m

a = acceleration

a = -vi2/(2x) = -(32.0 m/s)2 / [2(30.0 m)] = -17.06 m/s2

The negative sign indicates it is a deceleration.

Newton's 2nd law:

F = ma = (800 kg)(-17.06 m/s2) = -13648 N

The negative sign indicates the force is opposing the direction of motion.  The magnitude of the force is

|F| = 13648 N

momentum of soft ball three times less than baskey ball

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000