The basketball coach tells his team to run sprints back and forth across the court, which is 30 m long. they start at the left end of the court, run back and forth 6 times, then end back at the left end of the court where they began. what distance did they run? what is their displacement?

Distance is the total length of an object's path. Displacement is the overall change in position, ie. how far an object is from its initial position.

The court is 30 m long, so a path going back and forth once is 60 m long. Going along this path 6 times totals 360 m.

The end point is the same as the starting point, so the displacement is 0 m.

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

answer: question1

1,000 tons

question2

3: 8

question 3

store d

step-by-step explanation: