Ahot air balloon pilot wants the balloon to quickly rise several feet higher so it will be above some trees in the distance. which best explains how the pilot can make the balloon rise? 1. the pilot can adjust the temperature inside the balloon so it is equal to the temperature of the surrounding air. 2. the pilot can adjust the density of the air inside the balloon so it is equal to the density of the surrounding air. 3. the pilot can decrease the temperature inside the balloon so it is cooler than the surrounding air.

The correct answer is (D) The pilot can increase the temperature inside the balloon so it is warmer than the surrounding air.

This is based on the phenomenon that warm air rises up so the pilot should increase the temperature inside the balloon as compared to the surrounding air. This will rise the balloon up. The hot air will make the balloon  go up fastly.

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explanation:

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer