Point charges q1=+2.00μc and q2=−2.00μc are placed at adjacent corners of a square for which the length of each side is 1.50 cm . point a is at the center of the square, and point b is at the empty corner closest to q2. take the electric potential to be zero at a distance far from both charges. part a what is the electric potential at point a due to q1 and q2? express your answer with the appropriate units.

Explanation :

It is given that,

Side of square,

It is given that, the potential at point c is equal to zero.

So, potential at point a due to and   is given as:

where,

So,    (Since, is negative)

Hence, the potential at a due to and   is equal to 0 V.

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation:

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2