A1000-kg weather rocket is launched straight up. the rocket motor provides a constant acceleration for 16-s, then the motor stops. the rocket altitude 20-s after launch is 510-m. you can ignore any effects of air resistance. a. what was the rocket’s acceleration during the first 16-s? b. what is the rocket’s speed as it passes through a cloud 5100-m above the ground?

To solve this problem we use kinematics formulas.

to. What was the acceleration of the rocket during the first 16-s?

Where

= speed after 16 s

= initial velocity = 0

= acceleration during 16 s

Now we use the formula for the position:

Where:

= position after 16 s

= initial position = 0

= 16 s

Then, we know that the altitude of the rocket after 20 s is 5100 meters.

Then we will raise the equation of the position of the rocket from the instant to

where:

Now we clear .

The aceleration is

So:

What is the speed of the rocket when it passes through a cloud at 5100 m above the ground?

The speed is 392.32 m/s

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c. magnitude and direction