Aball is thrown straight up into the air with a speed of 21 m/s. if the ball has a mass of 0.1 kg, how high does the ball go? acceleration due to gravity is g = 9.8 m/s^2. a. 22.5 m b. 20.0 m c. 25.0 m d. 17.5 m

Hi!

The answer would be 22.5m

To calculate the distance the ball travels, you would need to apply the following formula from the equations of motion for an accelerating object:

2as = v^2 - u^2

Where a is acceleration due to gravity, 9.8m/s^2

s is the distance traveled by the object (height of ball in this case)

v is the final velocity, which we know will be zero at the point where the ball reaches maximum height.

u is the initial velocity, which is known to us as 21m/s

Rearranging the equation to solve for the height:

s = (v^2 - u^2 ) / 2a

s = ( 0^2 - 21^2 ) / 2(-9.8)

s = - 441/ - 19.6

s = 22.5m

Note: since gravity is acting against the object's motion, it will be negative

Hope this helps!

answer: f

explanation: g

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.