Me haha i’m so confused on my physics rn

The equation that you want for this is Vf^2 = Vi^2+2(a)*(deltaX)

Vf is your final velocity - in this case 233 m/s.

Vi is you initial velocity - in this case 119 m/s.

a is acceleration - in this case 17.7 m/s^2

deltaX is the change in your x position - what you are trying to find

plug everything in and solve for deltaX and you get 1133.56 m

graph slopes whilst gas cools, then it is flat whilst conensation to liquid happens, the coolong liquid then graphs as a slope when it solidifies graph is flat

latent heat