Ahelium balloon has a volume of 2.00 l at 101 kpa. as the balloon rises, the pressure drops to 97.0 kpa. what is the new volume?

The new volume is 2.1 L.

Explanation:

Use the formula Boyle's law.

Here, are the initial pressure and the final pressure and are the initial and the final volumes.

As, it is given in the problem, a helium balloon has a volume of 2.00 L at 101 kPa. As the balloon rises, the pressure drops to 97.0 kPa.

Put P_{1}=101 kPa,V_{1}=2.00L and P_{2}=97.0 kPa.

Therefore, the new volume is 2.1 L.  

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

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