Car a start 10 meters ahead of car b. car a moves at v= (3.0i+0j) m/s and car b moves forward at v=(7.0i+0j)m/s how many seconds does it takes car b to catch up

Do both cars leave the starting line at the same time ?  That's kind of important.  I'll assume that they both start out at the same time, and now I'll proceed to answer the question that I have invented.

-- Car B moves 4 m/s faster than Car A .  

-- So Car-A's lead shrinks by 4 meters every second after they start.

-- It takes (10/4) = 2.5 seconds for Car-A's lead to shrink to zero.

-- So Car-B overtakes Car-A 2.5 seconds after they start.

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

h o h o hope you have a merry christmas!

because if the tool that you are using is not balanced it there would be false mass.