An acorn falls from a tree. how fast is the acorn moving after 1.2 seconds?

a. 9.8 m/s
b. 1.2 m/s
c. 8.2 m/s
d. 11.8 m/s

D. 11.8 m/s

Using the equation;

v = u + at; such that v is the velocity attained, u is the initial velocity and a is the acceleration;

In our case, acorn falling from a tree is described as free fall aided by gravity;

Therefore, initial velocity is zero, u = 0, and the acceleration is due to gravity, thus, a = 9.8 m/s² , t = 1.2 seconds

Thus;

The equation becomes;

v = gt , since; u =0, and a = g = 9.8 m/s²

v = 9.8 × 1.2

  = 11.76 m/s

≈ 11.8 m/s

1 a

2 b

3 b

4 d

5 d

6 d

explanation:

pe = weightxheight = 2000x1000=2,000,000joules