1-a train travels 100 km to reach town a in one hour and 15 min. the train stops at station a for 45 minutes. then it travels 150 km to station b in 2 hours. what is the average velocity of the train?
average velocity= displacement/time

2-a car accelerates uniformly at the rate of 1.2 meters per second squared for a distance of 75 meters. if the truck started with a initial velocity of 6 meters per second, what is its velocity at the end of the 75 meters?
vf^2=vi^2 + 2as

Answer 1) : 62.5 km/hour is the average velocity of the train.

2) The final velocity of the car at the end of 75 m is 14.69 m/s

Explanation:

1) Displacement of the train = 100 km + 150 km = 250 km

Total time train took =1 hour 15 min+ 45 min + 2 hours = 240 min = 4 hours

Average velocity=

62.5 km/hour is the average velocity of the train.

2) The acceleration of the car, a= 1.2

Distance covered by the car,s = 75 m

Initial velocity of the car , = 6 m/s

Final velocity of thre car ,=?

Using third equation of motion:

The final velocity of the car at the end of 75 m is 14.69 m/s

do you have a formula possibly

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day