Askier moving at 5.30 m/s encounters a long, rough horizontal patch of snow having coefficient of kinetic friction 0.220 with her skis. how far does she travel on this patch before stopping?

6.5 m

Explanation:

First of all, we need to compute the acceleration of the skier. We know that there is only force acting on the skier: the force of friction, which is in the opposite direction to the motion of the skier. Using 2nd Newton Law:

where is the force of friction, with

is the coefficient of kinetic friction

m is the mass of the skier

is the acceleration due to gravity

Re-arranging the equation, we find:

So now we can use the following SUVAT equation to calcualte the total displacement of the skier before stopping:

where

v = 0 is the final velocity

u = 5.30 m/s is the initial velocity

a = -2.16 m/s^2 is the acceleration

d = ? is the displacement

Solving the formula for d, we find:

what is the actual question though?