Two light bulbs operate at the same voltage . why does the bulb with fewer ohms have more watts

Consider the formula W = E^2/R

E is the same for both bulbs. Everything depends on R

Let us suppose that E = 100 volts (high consumption day).

Let us further suppose that r = 2 ohms

W = 100^2 / 2

W = 10,000 / 2

W = 5000 watts . (It's just a number).

The second bulb  has a resistance of 1 ohm.

W = 100^2 / 1

W = 10000 watts.

The lower the resistance the higher the wattage.