Aparticle with charge 8 µc is located on the x-axis at the point −10 cm , and a second particle with charge 3 µc is placed on the x-axis at −8 cm . −10−8 −6 −4 −2 2 4 6 8 10 8 µ c 3 µ c − 3 µ c x → (cm) what is the magnitude of the total electrostatic force on a third particle with charge −3 µc placed on the x-axis at 2 cm

Force on -7 uC charge due to charge placed at x = - 10cm

now we will have

towards left

similarly force due to -5 uC charge placed at x = 6 cm

now we will have

towards left

Now net force on 7 uC charge is given as

towards left

Explanation:

i think it's 35 meters

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.