Auniform electric field of magnitude 112 kv/m is directed upward in a region of space. a uniform magnetic field of magnitude 0.82 t perpendicular to the electric field also exists in this region. a beam of positively charged particles travels into the region. determine the speed of the particles at which they will not be deflected by the crossed electric and magnetic fields. (assume the beam of particles travels perpendicularly to both fields.)

Explanation:

The beam of positively charged particles would not be deflected if the electric force acting on them is equal to the magnetic force:

where

q is the charge of the particles

E is the magnitude of the electric field

v is the speed of the particles

B is the intensity of the magnetic field

is the angle between the direction of v and B

Since the beam of particles travels perpendicular to the magnetic field, we have . So, we can rewrite the equation as

where

Substituting into the formula,

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .