When you jump from an elevated position you usually bend your knees upon reaching the ground. by doing this, you make the time of the impact about 10 times as great as for a stiff legged landing. in this way, the average force your body experiences

about 1/10th as great by bending your legs 

Time extended decreases acceleration value. 

solve using Newton's 2nd and Uniform Acceleration Laws. plug in values for descending. 

Vf = 0.0 m/s 

Vi = 10 m/s 

t = 1 s 

Acceleration is given by 

a = [Vf - Vi] / t 

a = [ (0.0 m/s) - (10 m/s) ] / (1 s) 

a = [ -10 m/s ] / (1 s) 

a = -10 m/s^2 

Solve the same thing, but with time 10x, so t = 10 s 

a = [ (0.0 m/s) - (10 m/s) ] / (10 s) 

a = [ -10 m/s ] / (10 s) 

a = -1 m/s^2 

Solve for first force and second force, using a mass of 100 kg 

F = m * a 

F = (100 kg) * (-10 m/s^2) 

F = -1,000 N 

F = (100 kg) * (-1 m/s^2) 

F = -100 N 

So divide long-force by short-force 

(-100 N) / (-1,000 N) = 0.1 (which is 1/10)

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west