Amodern compact fluorescent lamp contains 1.4 mg of mercury (hg). if each mercury atom in the lamp were to emit a single photon of wavelength 508 nm, how many joules of energy would be emitted?

a. 1.64 j
b. 3.3 j
c. 6.6 x 10^2 j
d. 3.3x10^3 j
e. 4.2 x 10^18 j

A. 1.64 J

Explanation:

First of all, we need to find how many moles correspond to 1.4 mg of mercury. We have:

where

n is the number of moles

m = 1.4 mg = 0.0014 g is the mass of mercury

Mm = 200.6 g/mol is the molar mass of mercury

Substituting, we find

Now we have to find the number of atoms contained in this sample of mercury, which is given by:

where

n is the number of moles

is the Avogadro number

Substituting,

atoms

The energy emitted by each atom (the energy of one photon) is

where

h is the Planck constant

c is the speed of light

is the wavelength

Substituting,

And so, the total energy emitted by the sample is

lexy is right because she has the labeled s

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.