An object is 16.0cm to the left of a lens. the lens forms an image 36.0cm to the right of the lens.

part a what is the focal length of the lens?
part b is the lens converging or diverging?
part c if the object is 8.00 mm tall, how tall is the image?
part d is it erect or inverted?

A) 11.1 cm

We can find the focal length of the lens by using the lens equation:

where

f is the focal length

p = 16.0 cm is the distance of the object from the lens

q = 36.0 cm is the distance of the image from the lens (taken with positive sign since it is on the opposide side to the image, so it is a real image)

Solving the equation for f:

B) Converging

The focal length is:

- Positive for a converging lens

- Negative for a diverging lens

In this case, the focal length is positive, so it is a converging lens.

C) 18.0 mm

The magnification equation states that:

where

is the heigth of the image

is the height of the object

Solving the formula for , we find

So the image is 18 mm high.

D) Inverted

From the magnification equation we have that:

- When the sign of is positive, the image is erect

- When the sign of is negative, the image is inverted

In this case, is negative, so the image is inverted.

answer///scientific method;

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