Aray of light strikes a flat mirror at an angle as shown in the illustration. note that, in this side‑view illustration, the mirror is laying flat on the ground. the arrow represents the direction that the incoming (or incident) ray of light is traveling and the angle at which it strikes the mirror. a light ray comes in from the left and strikes the mirror at a 30 degree angle. which of the illustrations represents the direction the ray of light is traveling after it reflects off the mirror? note that, in each picture, the arrow represents a possible direction the ray of light could travel and the possible angle at which it leaves the mirror. a light ray departs the mirror's surface at a 30 degree angle, moving right. a light ray departs the mirror's surface at a 30 degree angle, moving left. a light ray departs the mirror's surface at a 90 degree angle, moving straight up. a light ray departs the mirror's surface at a 60 degree angle, moving right.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

not moving. pos accel,

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .