Alightbulb is rated by the power that it dissipates when connected to a given voltage. for a lightbulb connected to 120 v household electricity, decreasing the resistance of the filament will the current through the bulb and the power dissipated by the bulb.

decrease, decrease
decrease, increase
increase, increase
increase, decrease

Increase, increase

Explanation:

For a light bulb, voltage, resistance and current follows the Ohm's law:

where

V is the voltage

R is the resistance

I is the current

In this problem, the voltage is fixed: V=120 V. We can rewrite the equation as

(1)

we see that the current is inversely proportional to the resistance: so, if we decrease the resistance of the filament, the current will increase.

Moreover, the power dissipated by the bulb is

which can be rewritten using (1) as

We see that the power dissipated is inversely proportional to the resistance: therefore, if we decrease the resistance of the filament, the power dissipated will increase.

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explanation:

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