Ahorizontal force of 2500 n is applied for a time of 30 seconds to the car mass of 1000 kg if the car is at rest and friction is negligible determine the distance travelled by the car

Newton’s second law: F=ma. 2500=1000a. a=2.5m/s*s. Final velocity is 2.5*30=75m/s. Average speed is (Vi+Vf)/2, which is 37.5m/s. D=vt. 37.5*30=1125m. The distance traveled is 1125 meters

this could be newton#'s law of cooling. the cooling curve is exponential