Abody of mass 10kg and initially at rest is subjected to a force of 20n for 1 second. calculate the kinetic energy during that time

20 J

Explanation:

First find the acceleration:

F = ma

20 N = (10 kg) a

a = 2 m/s²

Now find the final velocity:

v = at + v₀

v = (2 m/s²) (1 s) + 0 m/s

v = 2 m/s

Now find the final kinetic energy:

KE = 1/2 mv²

KE = 1/2 (10 kg) (2 m/s)²

KE = 20 J

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it

c. magnitude and direction