When a particle of charge q moves with a velocity v⃗ in a magnetic field b⃗ , the particle is acted upon by a force f⃗ exerted by the magnetic field. to find the direction and magnitude of this force, follow the steps in the following tactics box. keep in mind that the right-hand rule for forces shown in step 2 gives the direction of the force on a positive charge. for a negative charge, the force will be in the opposite direction. if the magnetic field of the wire is 4.0×10−4 t and the electron moves at 6.0×106 m/s , what is the magnitude f of the force exerted on the electron? express your answer in newtons to two significant figures.