Albert dressed as two-face flips a coin up in the air at an upward velocity of 5.00 m/s. he fails to catch it on the way down and it falls down an 8.5 m deep well. calculate the maximum height and maximum magnitude (could be positive or negative) of velocity of the coin.

1.28 m, 14 m/s

Explanation:

At the maximum height, the velocity is 0.

Given:

a = -9.8 m/s²

v₀ = 5.00 m/s

v = 0 m/s

x₀ = 0 m

Find:

x

v² = v₀² + 2a(x - x₀)

(0 m/s)² = (5.00 m/s)² + 2(-9.8 m/s²) (x - 0 m)

x = 1.28 m

The maximum speed is at the bottom of the well.

Given:

a = -9.8 m/s²

v₀ = 5.00 m/s

x₀ = 0 m

x = -8.5 m

Find:

v

v² = v₀² + 2a(x - x₀)

v² = (5.00 m/s)² + 2(-9.8 m/s²) (-8.5 m - 0 m)

v = -13.8 m/s

Rounded to 2 sig-figs, the maximum speed is 14 m/s.

answer would be d.) i hope this

explanation:

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards