A6.0-ohm resistor that obeys ohm’s law is connected to a source of variable potential difference. when the applied voltage is decreased from 12 v to 6 v, the current passing through the resistor a. remains the same b. is doubled c. is halved d. is quadrupled

The correct option is

(c) is halved.

Given a 6Ω resistor and the voltage is decreased from 12V to 6V

Ohm's Law:

Ohm's law states that the current (I) is directly proportional to the voltage (V) and inversely proportional to the resistance (R). That is

V= I/R

here, according to the question

initially, V = 12V and R = 6Ω

so I = 12V/6Ω = 2A

Finally

V = 6V and R = 6Ω

I' = 6V/6Ω = 1A

so we see that

2I' = I

I' = I/2

Hence, the current is halved.

Learn more about Ohm's Law:

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Is halved. A 6Ω resistor connected to a voltage source which voltage is decreased from 12V to 6V the current passing through the resistor is halved.

The key to solve this problem is applying Ohm's Law V = R I, clearing I from the equation, we obtain I = V/R. Then, the current is directly proportional to the voltage and inversely proportional to the resistance.

V = 12V and R = 6Ω

I = 12V/6Ω = 2A

V = 6V and R = 6Ω

V = 6V/6Ω = 1A

As we can see the current is halved if the voltage descreased from 12V to 6V

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