Arifle bullet with mass 8.00 g strikes and embeds itself in a block with mass 0.992 kg that rests on a frictionless, horizontal surface and is attached to a coil spring. the impact compresses the spring 15.0 cm. calibration of the spring shows that a force of 0.750 n is required to compress the spring 0.250 cma) find the magnitude of the block's velocity just after impact. b) what was the initial speed of the bullet?

ok so here we go

Explanation:

(ma)(va,1)+(mb)(vb,1)=(ma+mb)(v2)(ma)(va,1)+(mb)(vb,1)=(ma+mb)(v2).

Plugging in the givens results in (.008)(va,1)=v2(.008)(va,1)=v2.

Then, I considered the energies of the system as a whole. Spring force is conservative.

I reason that at the point at which the spring is at maximum compression of .15 m, the final velocity of the block is zero.

So, (1/2)(ma)(va,1)2=(1/2)(300)(.15)2(1/2)(ma)(va,1)2=(1/2)(300)(.15)2

I get 300 as the spring constant because F=kxF=kx.

Solving for va,1va,1, I got 29.0 m/s. I then multiplied 29.0 by .008 to get the velocity of the system, v2

(1/2)(ma+mb)(v2)2

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

the ima (higher than 1m) will be greater than the ima with the height of 1m.