Several wires of varying thickness are all made of the same material and all have the same length. if the wires are arranged in order of decreasing thickness, what can be said about the ordering of their resistance? a. the wires will be arranged in order of increasing resistance. b. the wires will be arranged in order of decreasing resistance. c. the ordering of the resistances can not be determined because the resistivity is not given. d. the ordering of the resistances can not be determined because the length is not given.

A. The wires will be arranged in order of increasing resistance.

Explanation:

The resistance of a wire is given by

where

is the resistivity of the material

L is the length of the wire

A is the cross-sectional area of the wire

In this problem we have several wires made of the same material (so, same ) and same length (same L): so, the only quantity that changes is their thickness, so their value of A.

We see from the formula that the resistance R is inversely proportional to the cross-sectional area A: therefore, the smaller the value of A, the larger the value of R. This means that if we arrange the wires in order of decreasing thickness, we are arranging the wires in order of increasing resistance.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

pretty sure it's false