Asmall bouncy ball with a momentum of 8 kg∙m/s to the left approaches head-on a large door at rest. the ball bounces straight back with a momentum of 6 kg∙m/s. what is the change in the momentum of the ball? what is the impulse exerted on the ball? what is the impulse exerted on the door?

-14 kg m/s

Explanation:

Taking the  direction "to the left" as positive direction, the initial momentum of the ball is

p1 = +8 kg m/s

while the final momentum is

p2 = -6 kg m/s

so the change in momentum is

According to the impulse theorem, the impulse exerted on the ball is equal to the change in momentum of the ball, so:

(which means 14 kg m/s to the right)

While the impulse that the ball exerted on the ball is equal and opposite in direction, so:

(which means towards the left)

the diagram which shows forces as either balanced = same speed or unbalanced = accelerarting

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.