The voltage, v, (in volts) across a circuit is given by ohm's law: v = ir, where i is the current (in amps) flowing through the circuit and r is the resistance (in ohms). if we place two circuits, with resistance r1 and r2, in parallel, then their combined resistance, r, is given by (1 / r) = (1 / r1) + (1 / r2) . suppose the current is 3 amps and increasing at 10^−2 amp/sec and r1 is 4 ohms and increasing at 0.5 ohm/sec, while r2 is 4 ohms and decreasing at 0.1 ohm/sec. calculate the rate at which the voltage is changing. (round your answer to four decimal places.)