An aluminum bar is 2 m long at temperature of 20 degrees c what was the length of the bar be at temperature hundred degrees celsius

L=2.003696

Explanation:

The question is on expansion due to heat

The general formulae is;

L= L₀ { 1+∝(T₂-T₁)}

where L₀ is initial length of bar at 20°, L is length of bar at asked temperatures, ∝ = 23.1× 10^-6 °c , T₂ is the final temperature, T₁ is the initial temperature in °c

Given;

L₀=2m

T₂=100°c

T₁=20°c

∝ = 23.1× 10^-6 °c

Substitute values in the equation

L= L₀ { 1+∝(T₂-T₁)}

L=2{1+23.1× 10^-6(100-20)}

L=2{1.001848}

L=2.003696

what was the answer?