If the resistance in a circuit connected to a constant current is halved, how is the voltage in the circuit affected? 1. the voltage remains constant.2. the voltage is reduced by a factor of 4.3. the voltage is quadrupled.4. the voltage is reduced by a factor of 2.5. the voltage is doubled.

4. The voltage is reduced by a factor of 2

Explanation:

The relationship between voltage, current and resistance in a circuit is given by Ohm's law:

V = RI

where

V is the voltage

R is the resistance

I is the current

In this problem,

the resistance in the circuit is halved: R' = R/2

the current is constant : I' = I

So the new voltage is

so the voltage is reduced by a factor 2.

answer: b.

explanation:

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer