The rate at which a body cools also depends on its exposed surface area s. if s is a constant, then a modification of (2), given in section 3.1, is dt dt = ks(t − tm), where k < 0 and tm is a constant. suppose that two cups a and b are filled with coffee at the same time. initially, the temperature of the coffee is 145° f. the exposed surface area of the coffee in cup b is twice the surface area of the coffee in cup a. after 30 min the temperature of the coffee in cup a is 95° f. if tm = 65° f, then what is the temperature of the coffee in cup b after 30 min? (round your answer to two decimal places.)