Adielectric-filled parallel-plate capacitor has plate area a = 30.0 cm2 , plate separation d = 9.00 mm and dielectric constant k = 3.00. the capacitor is connected to a battery that creates a constant voltage v = 15.0 v . throughout the problem, use ϵ0 = 8.85x10-12 c2/n. m2 . find the energy u1 of the dielectric-filled capacitor.

Explanation:

The capacitance of the parallel-plate capacitor is given by

where

ϵ0 = 8.85x10-12 C2/N.m2 is the vacuum permittivity

k = 3.00 is the dielectric constant

is the area of the plates

d = 9.00 mm = 0.009 m is the separation between the plates

Substituting,

Now we can calculate the energy of the capacitor, given by:

where

C is the capacitance

V = 15.0 V is the potential difference

Substituting,

a.metals can become magnetic if they have many spinning electrons that create magnetic fields.d.only some metals are attracted by magnets; these metals are called ferromagnetic.

d.wrapping an insulated wire around a metal with ferromagnetic properties and applying an electric current.