Aparticle with mass 1.81×10−3 kg and a charge of 1.22×10−8 c has, at a given instant, a velocity v⃗ =(3.00×104m/s)j^. what are the magnitude and direction of the particle’s acceleration produced by a uniform magnetic field b⃗ =(1.63t)i^+(0.980t)j^?

The magnitude and direction of the acceleration of the particle is

Explanation:

Given that,

Mass

Velocity

Charge

Magnetic field

We need to calculate the acceleration of the particle

Formula of the acceleration is defined as

We need to calculate the value of

Now, put the all values into the acceleration 's formula

Negative sign shows the opposite direction.

Hence, The magnitude and direction of the acceleration of the particle is

low freq = 100 mhz

low wavelength =101.7m

length = 3x10^8/freq

nah.   i'm just sleepy.