Ajet airplane lands with a speed of 120 mph. it has 1800 ft of runway after touch- down to reduce its speed to 30 mph. compute the average acceleration required of the airplane during braking a: a -8.1 ft/s2

The average acceleration is 8.06 m/s².

Explanation:

It is given that,

Initial speed of the jet, u = 120 mph = 176 ft/s

Final velocity of the jet, v = 30 mph = 44 ft/s

Distance, d = 1800 ft

We need to find the average acceleration required of the airplane during braking. It can be calculated using third law of motion as :

a = acceleration

So, the average acceleration required of the airplane during braking is -8.06 ft/s². Hence, this is the required solution.

come closer and become far apart and become steam/gas

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2