If you push twice as hard against a stationary brick wall, the amount of work you do

It remains zero

Explanation:

The work done on an object is given by:

where

F is the magnitude of the force applied

d is the displacement of the object

is the angle between the direction of the force and of the displacement

In this problem, the object is the wall, which is stationary. Therefore, the displacement of the wall is zero:

d = 0

And so, the work done is always zero, even if the force applied is twice as stronger.

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