A25.0−gsample of an alloy at 93.00°cis placed into 50.0 gof water at 22.00°cin an insulated coffee-cup calorimeter with a heat capacity of 9.20 j/k. if the final temperature of the system is 31.10°c, what is the specific heat capacity of the alloy?

1.23 J/(g °C)

Explanation:

= mass of water = 50 g

= specific heat of water = 4.186 J/(g °C)

= Initial temperature of water = 22.00 °C

= mass of alloy = 25 g

= specific heat of alloy = ?

= Initial temperature of alloy = 93.00 °C

= Final equilibrium temperature = 31.10 °C

Using conservation of heat

Heat Lost by alloy = Heat gained by water

=

(25) (93 - 31.10) = (50) (4.186) (31.10 - 22)

= 1.23 J/(g °C)

correct it is c.) b b

v=ir = 3x15 =45 v