(ii) a small fly of mass 0.22g is caught in a spider’s web. the web oscillates predominantly with a frequency of 4.0hz. (a) what is the value of the effective spring stiffness constantkfor the web? (b) at what frequency would you expect the web to oscillate if an insect of mass 0.44g were trapped?

(a) 0.139 N/m

(b) 2.83 Hz

Explanation:

(a) m = 0.22 g = 0.22 x 10^-3 kg

f = 4 Hz

The formula for the frequency of spring is given by

f =

Where, k be the spring constant

k = 0.139 N/m

(b)

m = 0.44 g = 0.44 x 10^-3 kg,

k = 0.139 N/m

Let the frequency be f.

f =

f = 2.83 Hz

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .