The rate constant for this second‑order reaction is 0.760 m−1⋅s−1 at 300 ∘c. a⟶products how long, in seconds, would it take for the concentration of a to decrease from 0.750 m to 0.330 m?

2.23 s

Explanation:

For a second-order reaction:

1 / [A] = 1 / [A]₀ + kt

Given [A] = 0.330 M, [A]₀ = 0.750 M, and k = 0.760 M⁻¹s⁻¹:

1 / 0.330 = 1 / 0.750 + 0.760t

t = 2.23

It would take 2.23 seconds.

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