If a load of 1000kg can just be dragged up an incline at 10 degrees to the horizontal by a force of 5kn applied in the most effective direction, what is the value offthe coefficient offriction?

The coefficient of friction is 0.34

Explanation:

It is given that,

Mass of the load, m = 1000 kg

It is dragged up an incline at 10 degrees to the horizontal by a force of 5 KN applied in the most effective direction, F = 5 × 10³ N

We need to find the coefficient of friction between the surface and the load.   From the attached figure, the load is dragged up with a force of F. A frictional force f will also act in this scenario.

So,

Since,

or  

So, the coefficient of friction is 0.34. Hence, this is the required solution.

moving ball hits still ball. mover stops, hit ball moves. momentum transfer.

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: