Physics, 29.01.2020 14:01 ramirez2184

How much work must be done by frictional forces in slowing a 1000-kg car from 26.1 m/s to rest? a.3.41 x 10^5 j b.2.73 x 10^5 j c.4.09 x 10^5 j d.4.77 x 10^5 j

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We have that for the Question "How much work must be done by frictional forces in slowing a 1000-kg car from 26.1 m/s to rest?" it can be said that work-done by frictional forces in slowing a 1000-kg car from 26.1 m/s to rest is

E=3.4*10^5 J

From the question we are told

How much work must be done by frictional forces in slowing a 1000-kg car from 26.1 m/s to rest?

a.3.41 x 10^5 J

b.2.73 x 10^5 J

c.4.09 x 10^5 J

d.4.77 x 10^5 J

Generally the equation for the Kinetic Energy is mathematically given as

$E=\frac{1}{2}*mv^2\\\\Therefore\\\\E=\frac{1}{2}*mv^2\\\\E=\frac{1}{2}*(1000)(26.1)^2\\\\$

E=3.4*10^5 J

Therefore

work-done by frictional forces in slowing a 1000-kg car from 26.1 m/s to rest is

E=3.4*10^5 J

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Answer from: yay47

Work done by the frictional force is $3.41\times 10^5\ J$

Explanation:

It is given that,

Mass of the car, m = 1000 kg

Initial velocity of car, u = 26.1 m/s

Finally, it comes to rest, v = 0

We have to find the work done by the frictional forces. Work done is equal to the change in kinetic energy as per work - energy theorem i.e.

W=k_f-k_i

$W=\dfrac{1}{2}m(v^2-u^2)$

$W=\dfrac{1}{2}\times 1000\ kg(0^2-(26.1\ m/s)^2)$

W = −340605 J

$W=3.41\times 10^5\ J$

Hence, the correct option is (a).

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

Answer from: Quest

A. they hold atoms together with a molecule.its a force that exist between molecules. hope this .

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