Aball is thrown at an angle of 45° to the ground. if the ball lands 79 m away, what was the initial speed of the ball? (round the answer to the nearest whole number. g = 9.8 m/s2)

The initial velocity of the ball is 28 m/s.

Explanation:

Given that,

Angle = 45°

Distance = 79 m

Using formula of horizontal and vertical distance

.....(I)

.....(II)

Put the value in both equation

Now,put the value of t in equation (II)

Hence, The initial velocity of the ball is 28 m/s.

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.